Handout Handout #33

MAE 3302 Aerodynamics of Incompressible Flow
Homework 10 Solutions

Answers to Study Questions

  1. Why won't the source panel method work for airfoil calculations?
    ans:    Because it is not capable of producing a circulation around the airfoil.
     
  2. What is a vortex panel?
    ans:    It is a vortex sheet of constant or simply varying strength placed on the surface of a body.
     
  3. Why are vortex panels needed for certain problems?
    ans:    In order to produce a net circulation.
     
  4. How can the lift be computed in a simple way when the vortex panel method is used? (You may want to try this in your program.)
    ans:    Using the Kutta-Joukowski law l = rU¥åj = 1NgjSj.
     
  5. Why is it best to use a combination of vortex and source panels for airfoil calculations as opposed to only vortex panels?
    ans:     Vortex panels alone are not effective since they induce no normal component of velocity on themselves. This means that the [u\vec]·[n\vec] boundary condition must be met entirely through the velocities induced by adjacent panels.
     
  6. In what ways have the NACA airfoil designs been improved in recent times? In what ways has the performance increased?
    ans:    Larger radius of curvature at the nose as well as reflexed lower surface near the trailing edge are now common. The maximum lift coefficient and the lift to drag ratios have increased.
     
  7. What role has the computer played in optimizing airfoils?
    ans:    The computer can evaluate various airfoil shapes very quickly. Thus it is possible to consider a much larger collection of airfoils than could be tested in a laboratory. It is also possible to automate the optimization process on the computer so that the best performance out of thousands of airfoil designs can be chosen.
     
  8. Why can't thin airfoil theory predict the onset of stall? How can one then determine Clmax?
    ans:    Because thin airfoil theory is strictly inviscid and stall is a viscous effect. Clmax can be estimated by combining thin airfoil theory with boundary layer theory. Often experimental measurements are required to determine Clmax concretely.
     
  9. What is meant by leading edge stall? What type of airfoil usually stalls in this way?
      ans:    A flow separation that begins near the leading edge and rapidly increases in size as the angle of attack is increases. Airfoils with moderate thickness ratios (10 to 16 percent) stall in this way.
     
  10. What is meant by trailing edge stall? What type of airfoil usually stalls in this way?
    ans:    A flow separation that begins near the trailing edge and increases in size as the angle of attack is increases. A thick airfoil usually stalls in this way.
     
  11. What is meant by thin airfoil stall? What type of airfoil usually stalls in this way?
    ans:    A separation that begins near the leading edge at fairly small angels of attack and then increases in size as the angle of attack is increases. Very thin airfoils, and flat plates in particular, usually stall in this way.
     
  12. What is the advantage of using a thick airfoil over a thin one?
    ans:    The maximum lift coefficient increases with thickness up to thickness of about 12%.
     
  13. Other things being equal, roughly what thickness will result in an airfoil with the highest possible Clmax?
    ans:    About 12%.
     
  14. How does a trailing edge flap work? What is its main objective?
    ans:    It increases camber which amounts to an upward shift in the lift curve, and ultimately to an increase in Clmax.
     
  15. How does a leading edge slat work? what is its main objective?
    ans:    It modifies the flow on the upper surface of the main airfoil such that stall is postponed to higher angles of attack. The net result is an increase in Clmax.
     
  16. Roughly how large can the lift coefficient be for an airfoil with both leading edge slats and trailing edge flaps? How does this compare with Clmax for the same airfoil with the high lift devices retracted?
    ans:    About 4.5. This is about 3 times the maximum lift coefficient for the same clean airfoil.
     
  17. By what factor is the stalling speed of an aircraft reduced by deploying a high lift system that results in a 50% increase in Clmax?
    ans:    Due to the square root dependence, roughly 25% (more exactly 1-Ö(1/1.5) = 0.18 or 18%).
     
  18. The high lift system shown in Figure 4.38 has not only tremendous lifting capability but also results in enormous drag. Is this a problem for its use? Why are there differences in the takeoff and landing configurations shown in Figure 4.37?
    ans:    Large drag is desirable for landing so that the aircraft can descent at a steep angle without increasing airspeed. Large drag is not wanted on takeoff and that explains the more moderate high-lift device settings for this flight operation.
     
  19. Why were most of the World War I aircraft relatively poor from an aerodynamic standpoint. What major advance was made by Prandtl and his group in Germany?
    ans:    Because they used very thin airfoils that could not achieve large lift coefficients. Prandtl's group recognized the advantage of thicker airfoil sections and these were incorporated in the design of the Fokker D-1 and D-VII.
     
  20. What is ideal incidence? How is airfoil performance enhanced if the airfoil is designed to operate at the ideal condition?
    ans:    It is the angle of attack where the forward stagnation point is located exactly at the leading edge. Flying at this condition, the airfoil has a much more gentle pressure distribution and consequently reduced skin friction.


File translated from TEX by TTH, version 2.00.
On 4 Dec 1999, 09:25.